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도서 Hindu calculations are made, are, on the one hand, the equality of the square of...에 대해 검색한
" Hindu calculations are made, are, on the one hand, the equality of the square of the hypothenuse in a right-angled triangle to the sum of the squares of the other two sides, and, on the other hand, the proportional relation of the corresponding parts... "
Translation of the Sûrya-Siddhânta: A Text-book of Hindu Astronomy; with ... - 38 페이지
1860 - 354 페이지
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A Course of Mathematics: Designed for the Use of the Officers and ..., 1-2권

Isaac Dalby - 1807 - 968 페이지
...angle PCO, &c. В If the radius CB or CG is 1, then GD it =04 the tine of 30" : and the cosine CD is equal to the square root of the difference between the squares of CG and GD (83, coro/.)« The square of 1 is I, and the square of 0*3 is о 25, their dif« frrcnce...
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Algebra: With Arithmetic and Mensuration

Brahmagupta - 1817 - 488 페이지
...the sum of hypotenuse and upright. The ground intercepled between the root and tip is the side: it is equal to the square root of the difference between the squares of the hypotenuse and upright. Hence the square of the side, divided by the sum of the hypotenuse and...
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A treatise on practical geometry, mensuration, conic sections, gauging, and ...

Ireland commissioners of nat. educ - 1834 - 370 페이지
...27 yards, what is its area ? Ans. 140-13. Note. When the triangle is isosceles, the perpendicular is equal to the square root of the difference between the squares of either of the equal sides and half the base. PROBLEM VII. Giren Ilie area and altitude of a triangle,...
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A Treatise on Mensuration for the Use of Schools

Commissioners of National Education in Ireland - 1837 - 290 페이지
...yards, what is its area '< Ans. 35-074. jVote. When the triangle is isosceles, the perpendicular is equal to the square root of the difference between the squares of either of the equal tides, and half the base. PROBLEM VII. Given the area a>id altitude of a triangle,...
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Journal of the American Oriental Society, 6권

American Oriental Society - 1860 - 632 페이지
...the one hand, the equality of the square of the hypothenuse in a right-angled triangle to the sum of the squares of the other two sides, and, on the other...text: it was plainly equal to the difference between the sine complement and radius. Again, the comparison of similar triangles showed that the chord of...
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The Practical Draughtsman's Book of Industrial Design: Forming a Complete ...

Jacques Eugène Armengaud (the Elder.), William Johnson - 1853 - 416 페이지
...the hypothenuse, as A c, be known, and one of the other sides, as AB, the third side, B c, will be equal to the square root of the difference between the squares of A c and A B. Thus assuming the above measures — BC = V25 — 9= The diagonal of a square is always...
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the practical draughtsman's book of industrial design, and machinist's and ...

william johnson - 1854 - 212 페이지
...the hypothenuse, as A c, be known, and one of the other sides, as AB, the third side, B c, will be equal to the square root of the difference between the squares of A c and A B. Thus assuming the above measures — B c = V25 — 9 = V16 = 4m. The diagonal of a square...
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The practical draughtsman's book of industrial design, tr. from the ..., 60호

William Johnson - 1860 - 442 페이지
...the hypothenuse, as A c, be known, and one of the other sides, as A в, the third side, B c, will be equal to the square root of the difference between the squares of AC and A в. Thus, assuming the above measures — в с = v/25 —'9 = v/Ï6 = 4 feet. The diagonal...
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Alternating Currents and Alternating Current Machinery: Being Volume II of ...

Dugald Caleb Jackson, John Price Jackson - 1896 - 760 페이지
...multiplied by .707. Consequently, the active pressure operating in a circuit with self-induction, is equal to the square root of the difference between the squares of the impressed and the inductive electric pressures. Or when Ea Eta and E, are respectively the active,...
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A Text-book on Electro-magnetism and the Construction of Dynamos, 2권

Dugald Caleb Jackson, John Price Jackson - 1896 - 760 페이지
...multiplied by .707. Consequently, the active pressure operating in a circuit with self-induction, is equal to the square root of the difference between the squares of the impressed and the inductive electric pressures. Or when Ea Et, and E, are respectively the active,...
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